To find only a single digit (such as “1”, or “2”) and replace (only) it, you have to add a plus after \\d.<\/p>\n\n\n\n
Something like:<\/p>\n\n\n\n
(\\d+)<\/p>\n\n\n\n
(to find<\/strong> it) and <\/p>\n\n\n\n \\1<\/p>\n\n\n\n to replace<\/strong> it.<\/p>\n\n\n\n For example you have to add a new element to these lines<\/p>\n\n\n\n You can use this regex<\/p>\n\n\n\n find<\/strong>: as a result you will get<\/p>\n\n\n\n To find only a single digit (such as “1”, or “2”) and replace (only) it, you have to add a plus after \\d. Something like: (\\d+) (to find it) and \\1 to replace it. For example you have to add a new element to these lines You can use this regex find: (\\d+) replace: \\n\\1 … <\/p>\n1 some first text \n3 some other text\n8 other text<\/code><\/pre>\n\n\n\n(\\d+)<\/code> replace<\/strong>: \\n\\1<\/code><\/p>\n\n\n\n\n1 some first text \n\n3 some other text\n\n8 other text<\/code><\/pre>\n","protected":false},"excerpt":{"rendered":"